hdu 1084 作业
#include <iostream> #include <vector> #include <algorithm> #include <string> #include <set> #include <queue> #include <map> #include <sstream> #include <cstdio> #include <cstring> #include <numeric> #include <cmath> #include <iomanip> #include <deque> #include <bitset> #include <cassert> //#include <unordered_set> //#include <unordered_map> #define ll long long #define pii pair<int, int> #define rep(i,a,b) for(int i=a;i<=b;i++) #define dec(i,a,b) for(int i=a;i>=b;i--) #define forn(i, n) for(int i = 0; i < int(n); i++) using namespace std; int dir[4][2] = { { 1,0 },{ 0,1 } ,{ 0,-1 },{ -1,0 } }; const long long INF = 0x7f7f7f7f7f7f7f7f; const int inf = 0x3f3f3f3f; const double pi = acos(-1.0); const double eps = 1e-6; const int mod = 1e9 + 7; inline ll read() { ll x = 0; bool f = true; char c = getchar(); while (c < '0' || c > '9') { if (c == '-') f = false; c = getchar(); } while (c >= '0' && c <= '9') x = (x << 1) + (x << 3) + (c ^ 48), c = getchar(); return f ? x : -x; } inline ll gcd(ll m, ll n) { return n == 0 ? m : gcd(n, m % n); } void exgcd(ll A, ll B, ll& x, ll& y) { if (B) exgcd(B, A % B, y, x), y -= A / B * x; else x = 1, y = 0; } inline int qpow(int x, ll n) { int r = 1; while (n > 0) { if (n & 1) r = 1ll * r * x % mod; n >>= 1; x = 1ll * x * x % mod; } return r; } inline int inv(int x) { return qpow(x, mod - 2); } ll lcm(ll a, ll b) { return a * b / gcd(a, b); } /**********************************************************/ const int N = 1e5 + 5; struct node { string time; int key, solve=0, grade; }; bool cmp1(node a, node b) { if (a.solve == b.solve) return a.time < b.time; return a.solve > b.solve; } bool cmp2(node a, node b) { return a.key < b.key; } int main() { int n; while (cin >> n,n!=-1) { vector<node> v; vector<int> a(6); rep(i, 1, n) { node t; cin >> t.solve >> t.time; t.key = i; v.push_back(t); a[t.solve]++; } sort(v.begin(), v.end(), cmp1); rep(i, 0, n - 1) { v[i].grade = v[i].solve * 10 + 50; if (v[i].solve == 4) { if (i - a[5] + 1 <= a[4] / 2) v[i].grade += 5; } if (v[i].solve == 3) { if (i - a[5]-a[4] + 1 <= a[3] / 2) v[i].grade += 5; } if (v[i].solve == 2) { if (i - a[5] -a[4]-a[3]+ 1 <= a[2] / 2) v[i].grade += 5; } if (v[i].solve == 1) { if (i - a[5] - a[4] - a[3] -a[2]+ 1 <= a[1] / 2) v[i].grade += 5; } } sort(v.begin(), v.end(), cmp2); rep(i, 0, n - 1) { cout << v[i].grade << endl; } cout << endl; } return 0; }