摘要: bzoj3309前戏∑ai=1∑bj=1f(gcd(i,j)) =∑ad=1∑ai=1∑bj=1e(gcd(i,j)==d)f(d) =∑ad=1∑a/di=1∑b/dj=1e(gcd(i,j)==1)f(d) =∑ad=1∑a/di=1∑b/dj=1∑d′|i且d′|jμ(d′)f... 阅读全文
posted @ 2017-01-16 08:53 DraZxlnDdt 阅读(123) 评论(0) 推荐(0) 编辑