摘要: 简单操作: 链式赋值:a = b = c = d = 1 交叉赋值:a,b = b,a 解压赋值(解压数量必须相等):list = [1,2,3,4,5] a,b,c,d,e = list 交互:input 判断语句:if a > 90: print('优秀') elif a < 90 and a 阅读全文
posted @ 2018-11-19 19:54 Dayle 阅读(208) 评论(0) 推荐(0) 编辑