SQL 判断两个时间段是否有交叉

费话不说，直接上代码

SQL 代码：

IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fun_GetTimeSlotDays]'))
DROP FUNCTION [dbo].fun_GetTimeSlotDays
GO

-- =============================================
-- Author:        <Mike.Jiang>
-- Create date: <2012-07-18>
-- Description:    <判断两个时间断是否有交叉,如果有则返回1,否则返回0>
-- =============================================
CREATE FUNCTION dbo.fun_GetTimeSlotDays(
@fromDate DATETIME,
@toDate DATETIME,
@startDate DATETIME,
@endDate DATETIME
)
RETURNS INT 
AS 
BEGIN
   DECLARE @ret INT;
   IF(DATEDIFF(DAY,@fromDate,@endDate)>=0 AND DATEDIFF(DAY,@endDate,@toDate)>=0 )
      SET @ret=1;
   IF(DATEDIFF(DAY,@startDate,@toDate)>=0 AND DATEDIFF(DAY,@toDate,@endDate)>=0 )
      SET @ret=1;
   IF (@ret is null)
      SET @ret=0;
   RETURN @ret;
END
GO

 

测试代码：

SELECT dbo.fun_GetTimeSlotDays('2012-03-01','2012-03-10','2012-02-10','2012-02-20');
SELECT dbo.fun_GetTimeSlotDays('2012-03-01','2012-03-10','2012-02-01','2012-03-01');
SELECT dbo.fun_GetTimeSlotDays('2012-03-01','2012-03-10','2012-03-01','2012-03-02');
SELECT dbo.fun_GetTimeSlotDays('2012-03-01','2012-03-10','2012-03-10','2012-03-11');
SELECT dbo.fun_GetTimeSlotDays('2012-03-01','2012-03-10','2012-03-11','2012-03-11');

测试结果：