javaweb中去除某个get方式的参数，并且返回路径 

 1 String requestURL = request.getRequestURL() + "";
 2             // String queryString = request.getQueryString();
 3             Enumeration<String> paraNames = request.getParameterNames();
 4             String queryparam = "";
 5             int tmp = 0;
 6             for (Enumeration e = paraNames; e.hasMoreElements();) {
 7                 String thisName = e.nextElement().toString();
 8                 if (StringUtils.isNotEmpty(thisName)
 9                         && !thisName.equals("code")) {
10                     if (tmp == 0) {
11                         queryparam = queryparam + thisName + "="
12                                 + request.getParameter(thisName);
13                     } else {
14                         queryparam = queryparam + "&" + thisName + "="
15                                 + request.getParameter(thisName);
16                     }
17                     tmp++;
18                 }
19             }
20 requestURL = requestURI + "?" + queryparam;

 获取参数参数值的方法是 request.getQuersyString();

关于getRequestURI与getRequestURL

posted @ 2016-01-20 23:53  ordinary01  阅读(1137)  评论(0)  编辑  收藏  举报