暴力破解unix/linux平台上采用crypt加密的口令
1 # coding=utf-8 2 3 ''' 4 暴力破解crypt模块加密的密码 5 ''' 6 7 import crypt 8 import optparse 9 10 usage = 'Usage: %prog [optinos] -p password.txt -d dictionary.txt' 11 parser = optparse.OptionParser(usage,version=1.0) 12 parser.add_option('-p',dest='pFile',action='store', 13 help='加密后的口令存放文件') 14 parser.add_option('-d',dest='dFile',action='store', 15 help='字典文件') 16 (options,args) = parser.parse_args() 17 18 def dection_passwords(password): 19 salt = password[:2] 20 dfile = open(options.dFile) 21 for word in dfile: 22 word = word.strip('\r\n') 23 cryptWord = crypt.crypt(word,salt) 24 if cryptWord == password: 25 print '找到密码,密码是：',word 26 return 27 print '未找到密码！' 28 return 29 30 def main(): 31 passfile = open(options.pFile) 32 for password in passfile: 33 password = password.strip('\r\n') 34 if password != '': 35 dection_passwords(password) 36 37 if __name__ == '__main__': 38 main()
运行后的结果是：
1 python ForceCrackCrypt.py -p /root/Desktop/password.txt -d /root/Desktop/dictionary.txt 2 找到密码,密码是： 123456 3 找到密码,密码是： 11111111 4 找到密码,密码是： abc123
