226 Invert Binary Tree

就是递归

class Solution:
    # @param {TreeNode} root
    # @return {TreeNode}
    def invertTree(self, root):
        if not root:
            return
        root.left, root.right = root.right, root.left
        self.invertTree(root.left)
        self.invertTree(root.right)
        return root

 

posted @ 2015-07-07 05:23  dapanshe  阅读(100)  评论(0编辑  收藏  举报