Decode Ways
A message containing letters from A-Z
is being encoded to numbers using the following mapping:
'A' -> 1 'B' -> 2 ... 'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.
For example,
Given encoded message "12"
, it could be decoded as "AB"
(1 2) or "L"
(12).
The number of ways decoding "12"
is 2.
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一开始理解错了,以为11可以是3种,其实是两种。
这题类似斐波那契数列
f(n)=f(n-1)+f(n-2);
不过这题是有条件的,要判断当所在位不为零,即是f(n-1),代表此次所得种类数不会增加,若为零,则不能这样拆,则这种情况不存在编码种类数。
1 class Solution { 2 public: 3 int numDecodings(string s) { 4 if(s.empty()) 5 return 0; 6 if(s.size()==1) 7 { 8 if(s[0]=='0') 9 return 0; 10 else return 1; 11 } 12 int tmp1=0,tmp2=1; 13 int len=s.size()-1; 14 if(s[len]!='0') 15 tmp1=1; 16 for(int i=len-1;i>=0;i--) 17 { 18 int res=0; 19 if(s[i]!='0') 20 res+=tmp1; 21 if(s[i]=='1'||(s[i]=='2'&&s[i+1]<='6')) 22 res+=tmp2; 23 tmp2=tmp1; 24 tmp1=res; 25 } 26 return tmp1; 27 } 28 };