POJ 1008 Maya Calendar

题目:http://poj.org/problem?id=1008

   玛雅人历法的一道题。

   不愧是POJ,看上去的一道水题都能这么恶心...这题WA了好多次

   最早是漏了uayet 这个月份

   然后是一年的最后一天当成了下一年

   下面这组数据:

   输入:4. uayet 259 输出:13 ahau 364

   只要过了这组数据就没问题了...

#include <iostream>
#include <string>
#include <stdio.h>
#include <cstdlib>

using namespace std;

string hname[19]={ "pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu","uayet"};
string tname[20]={ "imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau"};

int main()
{
    int n;
    cin>>n;
    cout<<n<<endl;
    for (int i = 0; i < n; i++)
    {
        int daynum=0;
        int hday,hyear;
        char t;
        string hmonth;
        cin>>hday;
        cin>>t;
        cin>>hmonth>>hyear;
        if(hyear>0)    daynum+=hyear*365;
        for (int j = 0; j < 19; j++)
        {
            if(hmonth==hname[j]) 
            {
                daynum+=j*20;
                break;
            }
        }
        daynum+=(hday+1);
        int tday=daynum%20;
        cout<<(daynum-1)%13+1<<" "<<tname[(daynum-1)%20]<<" "<<(daynum-1)/260<<endl;


    }
    

    return 0;
}

 

posted @ 2013-01-31 23:51  Daniel Qiu  阅读(253)  评论(0编辑  收藏  举报