c#根据某一个属性使用groupJoin拼接不同list
摘要:
var resultList = userList.GroupJoin(departList, u => u.departmentId, a => a.id, (u, a) => new { id = u.id, serialNumber = u.serialNumber, nickName = u 阅读全文
posted @ 2021-05-06 11:43 党鹏飞 阅读(320) 评论(0) 推荐(0) 编辑