杭电1012
u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18822 Accepted Submission(s): 8211
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
//杭电1012 #include <stdio.h> int main (int argc, char **argv) { printf("n e\n"); printf("- -----------\n"); printf("0 1\n"); printf("1 2\n"); printf("2 2.5\n"); double result = 2.5 ; double p = 0.5; for (int i = 3; i <= 9; ++ i ) { p /= i; result += p; printf("%d %.9f\n", i , result); } return 0; }