简单算法

冒泡排序

// 冒泡排序加去重
public static int[] DistinctAndOrder(int[] OldArray)
{
    if (OldArray != null && OldArray.Length > 0)
    {
        //排序
        for (int i = 0; i < OldArray.Length - 1; i++)
        {
            for (int j = 0; j < OldArray.Length - i - 1; j++)
            {
                if (OldArray[j] > OldArray[j + 1])
                {
                    int temp = OldArray[j];
                    OldArray[j] = OldArray[j + 1];
                    OldArray[j + 1] = temp;
                }
            }
        }
        //去重
        // return OldArray.Distinct().ToArray();
        List<int> NewArray = new List<int>();
        for (int i = 0; i < OldArray.Length-1; i++)
        {
            if (OldArray[i] != OldArray[i + 1])
            {
                if (i == OldArray.Length - 2)
                {
                    NewArray.Add(OldArray[i]);
                    NewArray.Add(OldArray[i+1]);
                }
                else
                {
                    NewArray.Add(OldArray[i]);
                }
            }
        }
        return NewArray.ToArray();
    }
    else
    {
        return new int[] { };
    }
}
int[] Ints =new int[] { 2, 3, 6, 2, 8, 9, 1, 2, 6, 8, 4 };
Console.WriteLine($"排序前:{string.Join(",", Ints)}");
var NewInts= TestClass.DistinctAndOrder(Ints);
Console.WriteLine($"排序后:{string.Join(",", Ints)}");
Console.WriteLine($"去重后:{string.Join(",", NewInts)}");

递归算法

 //递归
 public static int? DiGui(int n)
 {
     if (n > 0)
     {
         if (n == 1) return 1;
         else if (n == 2) return 1;
         else return DiGui(n - 1) + DiGui(n - 2);
     }
     else
     { 
         return null;
     }
 }
//测试递归 1、1、2、3、5、8、13、21......
Console.WriteLine("递归测试");
Console.WriteLine($"Fn(1)=>{TestClass.DiGui(1)}" );
Console.WriteLine($"Fn(2)=>{TestClass.DiGui(2)}");
Console.WriteLine($"Fn(3)=>{TestClass.DiGui(3)}");
Console.WriteLine($"Fn(4)=>{TestClass.DiGui(4)}");
Console.WriteLine($"Fn(30)=>{TestClass.DiGui(30)}");

 

posted @ 2024-08-09 00:04  DaiWK  阅读(2)  评论(0编辑  收藏  举报