Python 练习

(1)有四个数字:1、2、3、4,能组成多少个互不相同且无重复数字的三位数?各是多少?

 

#!python2
#-*- coding:utf-8 -*-

result=[]
for i in xrange(1,5):
    for j in xrange(1,5):
        for k in xrange(1,5):
            if i != j and i != k and j != k:
                result.append((i,j,k))
                
result
len(result)

 

(2)企业发放的奖金根据利润提成。利润(I)低于或等于10万元时,奖金可提10%;利润高于10万元,低于20万元时,低于10万元的部分按10%提成,高于10万元的部分,可提成7.5%;20万到40万之间时,高于20万元的部分,可提成5%;40万到60万之间时高于40万元的部分,可提成3%;60万到100万之间时,高于60万元的部分,可提成1.5%,高于100万元时,超过100万元的部分按1%提成,从键盘输入当月利润I,求应发放奖金总数?

 

#!python2
#-*- coding:utf-8 -*-

revenue=float(raw_input("Please input your revenue?"))

boundary=[1000000,600000,400000,200000,100000,0]
rate=[0.01,0.015,0.03,0.05,0.075,0.1]
bonus=0

for idx in xrange(6):
    if revenue>boundary[idx]:
        print "Over %d: %d" % (boundary[idx],(revenue-boundary[idx])*rate[idx])
        bonus+=(revenue-boundary[idx])*rate[idx]
        revenue=boundary[idx]
print "Total bonus is %d" % bonus

 

(3)一个整数,它加上100和加上268后都是一个完全平方数,请问该数是多少?(假定范围是10000以内)

 

#!python2
#-*- coding:utf-8 -*-

import math

for i in xrange(10000):
    x=int(math.sqrt((i+100)))
    y=int(math.sqrt(i+268))
    
    if (x*x==i+100) and (y*y==i+268) :
        print i

 

(4)输入某年某月某日,判断这一天是这一年的第几天?

 

#!python2
#-*- coding:utf-8 -*-

year=int(raw_input("please input year: "))
month=int(raw_input("please input month: "))
day=int(raw_input("please input day: "))

months=(0,31,59,90,120,151,181,212,243,273,304,334)

sum=0

if 0<month<=12:
     sum=months[month-1]
     
else:
    print "Please input a valid month!"
    

sum+=day

leap=0

if (year %400 ==0) or ((year%4==0) and (year%100!=0)):
    
    leap=1
    
    print "%d year is a leap year!" %year
    
if leap==1 and month >2:
    sum+=1
    
print "It is %dth day of year %d" %(sum,year)

 

(5)输入三个整数x,y,z,请把这三个数由小到大输出

 

#!python2
#-*- coding:utf-8 -*-

l1=[]

for i in xrange(3):
    x=int(raw_input("please input a int number: "))
    l1.append(x)
    
l1.sort()
print l1

 

(6)9*9 乘法口诀表

 

#!python2
#-*- coding:utf-8 -*-


for i in xrange(1,10):
    print 
    for j in xrange(1,i+1):
        print " %d * %d = %d " %(i,j,i*j),

 

(7)暂停一秒输出

 

#!python2
#-*- coding:utf-8 -*-


import time

d1={1:"a",2:"b"}

for k,v in d1.items():
    print k,v
    time.sleep(5)

 

(8) 暂停一秒输出,并格式化当前时间

 

#!python2
#-*- coding:utf-8 -*-


import time

print time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(time.time()))

time.sleep(10)

print time.strftime("%y-%m-%d %H:%M:%S",time.localtime(time.time()))

(9)古典问题:有一对兔子,从出生后第3个月起每个月都生一对兔子,小兔子长到第三个月后每个月又生一对兔子,假如兔子都不死,问每个月的兔子总数为多少?

 

#!python2
#-*- coding:utf-8 -*-

h = 0
leap = 1
from math import sqrt
from sys import stdout

for m in range(101,201):
    k = int(sqrt(m + 1))
    for i in range(2,k + 1):
        if m % i == 0:
            leap = 0
            break
    if leap == 1:
        print '%-4d' % m
        h += 1
        if h % 10 == 0:
            print ''
    leap = 1
print 'The total is %d' % h

 

(10)打印出所有的"水仙花数",所谓"水仙花数"是指一个三位数,其各位数字立方和等于该数本身

 

#!python2
#-*- coding:utf-8 -*-

for n in xrange(100,1000):
    i = n/100
    j=n/10%10
    z=n%10
    
    if n==i**3+j**3+z**3:
        print n

 

(11)将一个正整数分解质因数

#!python2
#-*- coding:utf-8 -*-

def func(n):
    print "{} =".format(n),
    if not isinstance(n,int) or n<=0:
        print "Please input a valid integer."
        exit(0)
    elif n==1:
        print "{}".format(n)
        
    while n!=1:
        
        for index in xrange(2,n+1):
            
            if n%index==0:
                
                n/=index
                
                if n==1:
                    print index
                else :
                    print "{} *".format(index),
                break
                              
func(100)

 

(12)一个排序

#!python2   
#-*- coding:utf-8 -*-

data_list=[]

data_list.append({"s":1,"v":1.1})
data_list.append({"s":10,"v":1.9})
data_list.append({"s":3,"v":1.6})
data_list.append({"s":2,"v":1.2})
data_list.append({"s":8,"v":1.4})

data_list

data_list.sort(key=lambda v:v.get("v"), reverse=False)

 

(13) 时间相关

 

#!python2   
#-*- coding:utf-8 -*-

import datetime

#输出今日日期,格式为 dd/mm/yyyy

today=datetime.datetime.today().strftime("%d/%m/%Y")

print today

#创建日期对象

birthday=datetime.date(2000,1,1)

print birthday.strftime("%d/%m/%Y")

#日期算术运算

tmp_date=birthday+datetime.timedelta(days=1)

print tmp_date.strftime("%d/%m/%Y")

#日期替换

replace_date=birthday.replace(year=2012)

print replace_date.strftime("%d/%m/%Y")

 

(14)输入一行字符,分别统计出其中英文字母、空格、数字和其它字符的个数

#!python2   
#-*- coding:utf-8 -*-

import string

s=raw_input("Please input a word: \n")
letters=0
space=0
digit=0
others=0
for c in s:

    if c.isalpha():
        letters+=1
    elif c.isspace():
        space+=1
    elif c.isdigit():
        digit+=1
    else:
        others+=1
print "letters=%d, space =%d, digit=%d,others=%d" %(letters,space,digit,others)
    
    

 

(15)求s=a+aa+aaa+aaaa+aa...a的值,其中a是一个数字。例如2+22+222+2222+22222(此时共有5个数相加),几个数相加有键盘控制

#!python2   
#-*- coding:utf-8 -*-

a=int(raw_input("Please input number: \n"))
n=int(raw_input("Please input loop times: \n"))
l=[]
tn=0
for i in xrange(n):
    tn=tn+a
    a=a*10
    l.append(tn)
    

sum_l=reduce(lambda x,y:x+y,l)    
print l
print sum_l

 

(16)一个数如果恰好等于它的因子之和,这个数就称为"完数"。例如6=1+2+3.编程找出1000以内的所有完数。

#!python2
#-*- coding:utf-8 -*-

for i in xrange(2,1001):
    k=[]
    n=-1
    s=i
    for j in xrange(1,s):
        if i%j==0:
            s-=j
            k.append(j)
            
    if s==0:
        print i
        print k

(17)一球从100米高度自由落下,每次落地后反跳回原高度的一半;再落下,求它在第10次落地时,共经过多少米?第10次反弹多高?

#!python2
#-*- coding:utf-8 -*-

t=[]
h=[]
h2=100.0
for i in xrange(1,11):
    t.append(h2)
    h2/=2.0
    h.append(h2)
    
print sum(t)
print h[9]

(18)猴子吃桃问题:猴子第一天摘下若干个桃子,当即吃了一半,还不瘾,又多吃了一个第二天早上又将剩下的桃子吃掉一半,又多吃了一个。以后每天早上都吃了前一天剩下的一半零一个。到第10天早上想再吃时,见只剩下一个桃子了。求第一天共摘了多少

#!python2
#-*- coding:utf-8 -*-

p=1
for i in xrange(9,0,-1):
    p=(p+1)*2
    
print p

(19)两个乒乓球队进行比赛,各出三人。甲队为a,b,c三人,乙队为x,y,z三人。已抽签决定比赛名单。有人向队员打听比赛的名单。a说他不和x比,c说他不和x,z比,请编程序找出三队赛手的名单。

#!python2
#-*- coding:utf-8 -*-

for i in range(ord('x'),ord('z') + 1):
    for j in range(ord('x'),ord('z') + 1):
        if i != j:
            for k in range(ord('x'),ord('z') + 1):
                if (i != k) and (j != k):
                    if (i != ord('x')) and (k != ord('x')) and (k != ord('z')):
                        print 'order is a -- %s\t b -- %s\tc--%s' % (chr(i),chr(j),chr(k))

 

(20)

#!python2
#-*- coding:utf-8 -*-

from sys import stdout


for i in xrange(4):
    for j in xrange(3-i):
        stdout.write(" ")
    for k in xrange(2*i+1):
        stdout.write("*")
    print 

for i in xrange(3):
    for j in xrange(i+1):
        stdout.write(" ")
    for k in xrange(5-2*i):
        stdout.write("*")
    print
        

 

(21) 有一分数序列:2/1,3/2,5/3,8/5,13/8,21/13...求出这个数列的前20项之和。

#!python2
#-*- coding:utf-8 -*-

#methon 1
a=1.0
b=2.0
s=0.0

for n in xrange(1,21):
    s+=b/a
    a,b=b,a+b
    
print s



a=1.0
b=2.0
s=0.0


#methon 2
l=[]
for n in xrange(1,21):
    l.append(b/a)
    a,b=b,a+b

s=reduce(lambda x,y:x+y,l)
print s

(22)求1+2!+3!+...+20!的和

#!python2
#-*- coding:utf-8 -*-

#methon 1

s=0
for n in xrange(1,21):
    j=1
    for i in xrange(1,n+1):
        j*=i
    s+=j
    
print s

#method 2

s=0
i=1
for n in xrange(1,21):
    i*=n
    s+=i
  
print s

#method 3

l=xrange(1,21)
s=0

def op(n):
    j=1
    for i in xrange(1,n+1):
        j*=i
    return j


s=sum(map(op,l))
print s

(23)利用递归方法求5!

#!python2
#-*- coding:utf-8 -*-

def fn_1(n):
    if n==0:
        sum=1
    else:
        sum=fn_1(n-1)*n
    return sum

for i in xrange(6):
    print fn_1(i)

(24)利用递归函数调用方式,将所输入的5个字符,以相反顺序打印出来

#!python2
#-*- coding:utf-8 -*-

def fn_1(s,l):
    if l==0:
        return
    print s[l-1],
    fn_1(s,l-1)
    
s=raw_input("Please input a string:")
l=len(s)

fn_1(s,l)

(25)有5个人坐在一起,问第五个人多少岁?他说比第4个人大2岁。问第4个人岁数,他说比第3个人大2岁。问第三个人,又说比第2人大两岁。问第2个人,说比第一个人大两岁。最后问第一个人,他说是10岁。请问第五个人多大?

#!python2
#-*- coding:utf-8 -*-

def fn_1(n):
    if n==1:
        c=10
        print c
        return
    else:
        c=fn_1(n-1)+2
        print c
    return c
    
fn_1(5)
    

(26)一个不多于5位的正整数,要求:一、求它是几位数,二、逆序打印出各位数字。

#!python2
#-*- coding:utf-8 -*-

n=int(raw_input("Please input a number:"))

a=n/10000
b=n%10000/1000
c=n%1000/100
d=n%100/10
e=n%10

if a!=0:
    print "5 位数:",e,d,c,b,a
elif b!=0:
    print "4 位数:",e,d,c,b
elif c!=0:
    print "3 位数:",e,d,c
elif d!=0:
    print "2 位数:",e,d
else:
    print "1 位数:",e
    
    
    





    

(27)一个5位数,判断它是不是回文数。即12321是回文数,个位与万位相同,十位与千位相同。

#!python2
#-*- coding:utf-8 -*-

#method 1

n=int(raw_input("Please input a number:"))

a=n/10000
b=n%10000/1000
d=n%100/10
e=n%10

if a==e and b==d:
    print "%d 是个回文数" %(n)
else:
    print "%d 不是个回文数"%(n)


#method 2

n=int(raw_input("Please input a number:"))
x=str(n)
flag=True

for i in xrange(len(x)/2):
    if x[i]!=x[-i-1]:
        flag=False
        break
        
if flag:
    print "%d 是个回文数" %(n)
else:
    print "%d 不是个回文数"%(n)

(28)请输入星期几的第一个字母来判断一下是星期几,如果第一个字母一样,则继续判断第二个字母

#!/usr/bin/python
# -*- coding: UTF-8 -*-

first_letter = raw_input("please input first letter(input Y abort):")

if first_letter.upper() == 'S':
    print ('please input second letter:')
    second_letter = raw_input("please input:")
    if second_letter.upper() == 'A':
        print ('Saturday')
    elif second_letter.upper()  == 'U':
        print ('Sunday')
    else:
        print ('data error')
    
elif first_letter.upper() == 'F':
    print ('Friday')
    
elif first_letter.upper() == 'M':
    print ('Monday')
    
elif first_letter.upper() == 'T':
    print ('please input second letter')
    second_letter = raw_input("please input:")
 
    if second_letter.upper()  == 'U':
        print ('Tuesday')
    elif second_letter.upper()  == 'H':
        print ('Thursday')
    else:
        print ('data error')
        
elif first_letter.upper() == 'W':
    print ('Wednesday')
else:
    print ('data error')

 

posted on 2017-03-07 14:06  大大的橙子  阅读(460)  评论(0编辑  收藏  举报

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