线性表之单链表(下)

话不多说,只要写了几个线性表的操作,其中包括:表的反转,表的相邻节点间data的最大值,以及2个链表按照顺序大小合并



// 头文件:link_list.h
typedef int data_t;

typedef struct node{
    data_t data;
    struct node *next;
}listnode, *linklist;

// 倒置链表
int list_reverse(linklist H);
// 相邻节点之间的最大值
linklist list_adjmax(linklist H, data_t *value);
// 2个链表按照顺序大小合并
int list_merge(linklist H1, linklist H2);
// link_list.c

# include <stdio.h>
# include <stdlib.h>
# include "link_list.h"
// 链表倒置
int list_reverse(linklist H){
	linklist p;
	linklist q;

	if (H == NULL){
		printf("H is NULL\n");
		return -1;
	}

	if (H->next == NULL || H->next->next == NULL){ // 只有一个节点
		return 0;
	}
	p == H->next->next;
	H->next->next == NULL;

	while (p != NULL)
	{
		q = p;
		p = p->next;

		q->next = H->next; // 将第n个链表的尾部将第一个链表的头部相连
		H->next = q; // 第n个链表的头和H相连
	}
	return 0;
}

// 链表相邻节点之间data的和取最大值
linklist list_adjmax(linklist H, data_t *value){
	linklist p, q, r;
	data_t sum;

	if (H == NULL){
		printf("H is NULL\n");
		return NULL;
	}
	if (H->next == NULL || H->next->next == NULL || H->next->next->next == NULL){ // 只有2个链表情况
		return H;
	}
	q = H->next;
	p = H->next->next;
	sum = q->data + p->data;

	while (p->next != NULL)
	{
		p = p->next;
		q = q->next;

		if (sum < q->data + p->data){
			sum = q->data + p->data;
			r = q;
		}
	}
	*value = sum;  // *指针表示,指针的某个空间的值
	return r;
	
}


int list_merge(linklist H1, linklist H2){
	linklist p, q,r;

	if (H1 == NULL || H2 == NULL){
		printf("H1 || H2 is null\n");
		return -1;
	}
	p = H1->next;
	q = H2->next;
	r = H1;
	H1->next = NULL;
	H2->next = NULL;

	while (p && q)
	{
		if(p->data <= q->data){
			r->next = p;
			p = p->next;
			r = r->next;
			r->next = NULL;
		}else{
			r->next = q;
			q = q->next;
			r = r->next;
			r->next = NULL;
		}
	}
	if (p == NULL){
		r->next = q;
	}else{
		r->next = p;
	}
	return 0;
}
posted @ 2023-09-22 15:14  dack_deng  阅读(11)  评论(0编辑  收藏  举报