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用递归求单链表中值最大的节点

Posted on 2013-06-15 16:35  NotOnlyJava  阅读(1319)  评论(0编辑  收藏  举报

如题:

    有某链表如下:

1 public class LinkNode {
2 
3     private int value;
4 
5     private LinkNode nextNode;
6 }

请用递归求链表值最大的节点,实现如下:

  1 package com;
  2 
  3 /**
  4  * 递归获取单链表值最大的节点
  5  * 
  6  * @author CaoZP
  7  *
  8  */
  9 public class LinkNode {
 10 
 11     private int value;
 12 
 13     private LinkNode nextNode;
 14 
 15     public LinkNode() {
 16 
 17     }
 18     
 19     
 20 
 21     public LinkNode(int value) {
 22         this.value = value;
 23     }
 24 
 25 
 26     public LinkNode(int value, LinkNode nextNode) {
 27         this.value = value;
 28         this.nextNode = nextNode;
 29     }
 30 
 31 
 32     public int getValue() {
 33         return value;
 34     }
 35 
 36     public void setValue(int value) {
 37         this.value = value;
 38     }
 39 
 40     
 41     public LinkNode getNextNode() {
 42         return nextNode;
 43     }
 44 
 45     public void setNextNode(LinkNode nextNode) {
 46         this.nextNode = nextNode;
 47     }
 48 
 49     
 50     @Override
 51     public String toString() {
 52         return "LinkNode [value=" + value + ", nextNode=" + nextNode + "]";
 53     }
 54     
 55     public void printNode()
 56     {
 57         StringBuilder str = new StringBuilder("[");
 58         LinkNode node = getNextNode(); 
 59         while(node!=null)
 60         {
 61             str.append(node.getValue()).append(",");
 62             node = node.getNextNode(); 
 63         }
 64         str.append("]");
 65         System.out.println(str);
 66     }
 67 
 68 
 69     public static void main(String[] args) {
 70           
 71         LinkNode head = new LinkNode(123);
 72         LinkNode node = new LinkNode(156);
 73         LinkNode node1 = new LinkNode(0);
 74         LinkNode node2 = new LinkNode(456);
 75         LinkNode node3 = new LinkNode(-100);
 76         LinkNode node4 = new LinkNode(2);
 77         
 78         head.setNextNode(node);
 79         node.setNextNode(node1);
 80         node1.setNextNode(node2);
 81         node2.setNextNode(node3);
 82         node3.setNextNode(node4);
 83 
 84         head.printNode();
 85 //        LinkNode maxNode = getMaxNode(head);
 86 //        System.out.println(maxNode);
 87         LinkNode minNode = getMinNode(head);
 88         System.out.println(minNode);
 89         
 90     }
 91 
 92 
 93 
 94     /**
 95      * 获取链表中值最大的节点
 96      * 
 97      * @param head
 98      * @return
 99      */
100     public static LinkNode getMaxNode(LinkNode head) {
101         if(head ==null)
102         {
103             throw new NullPointerException("arg is null");
104         }
105         //nextNode为空说明到了链尾
106         if(head.getNextNode()==null)
107         {
108             return head;
109         }
110         //当前节点的值大于nextNode把nextNode的nexNode设为head的nextNode
111         if(head.getValue()>head.getNextNode().getValue())
112         {
113             LinkNode childNextNode = head.getNextNode().getNextNode();
114             head.setNextNode(childNextNode);
115             return getMaxNode(head);
116         }else{
117         //否则就比较nextNode和nextNode的nextNode    
118             return getMaxNode(head.getNextNode());
119         }
120     }
121     /**
122      * 获取链表中值最大的节点
123      * 
124      * @param head
125      * @return
126      */
127     public static LinkNode getMinNode(LinkNode head) {
128         if(head ==null)
129         {
130             throw new NullPointerException("arg is null");
131         }
132         //nextNode为空说明到了链尾
133         if(head.getNextNode()==null)
134         {
135             return head;
136         }//0 15 56 -17 189
137         //当前节点的值大于nextNode把nextNode的nexNode设为head的nextNode
138         if(head.getValue()<head.getNextNode().getValue())
139         {
140             LinkNode childNextNode = head.getNextNode().getNextNode();
141             head.setNextNode(childNextNode);
142             return getMinNode(head);
143         }else{
144         //否则就比较nextNode和nextNode的nextNode    
145             return getMinNode(head.getNextNode());
146         }
147     }
148 }