摘要:
java提交注意package#pragma comment(linker, "/STACK:1024000000,1024000000")kmpvoid Next(int n){ int j=0,k=-1; next[0]=-1; while(j=n)return i-n; else return -1;}快速读入/* 可以负数,不能小数*/inline void inp( int &n ){ n=0; int ch=getchar_unlocked(),sign=1; while( ch '9' ){if(ch=='-')sign 阅读全文