C++求1!到n!的和

题目内容：求1!+2!+3!+4!+……+n!的结果。

输入描述：输入不多于50个正整数的数据n(1<=n<=12)。

输出描述：对于每个n，输出计算结果。每个计算结果应单独占一行。

参考代码：

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#include "stdafx.h" #include <fstream> #include <vector> #include <iostream> using namespace std;   int main(int argc,char * argv[]) {     vector<int> n(50);     int sum, p, m;     int num = 0;     while (num <= 49)     {         cin >>m;         if (m>= 1 && m<= 12)         {             n[num] = m;             num++;         }               else if (m<1 || m>12)         {             cout << "The input should be more than 1 and less than 12";         }         if (cin.get()=='\n')         {             break;         }     }           for (int j = 0; j < num; j++)     {         sum = 0;         p = 1;         for (int i = 1; i <= n[j]; i++)         {             p = p*i;             sum = sum + p;                  }         cout << sum << endl;     }       return 0; }

结果如图：