POJ 3106 Flip and Turn 模拟 分析
摘要:
--------const int maxn=400;const int maxm=200000;int n,m;char a[maxn][maxn];char b[maxn][maxn];int stk[10];int cnt;char s[maxm];char cd[7][3]={"1","CX","V","BY","2","AZ","H"};char sp[7][8]={"1","1H","1H1&q 阅读全文
posted @ 2014-01-10 00:27 电子幼体 阅读(134) 评论(0) 推荐(0) 编辑