import java.util.ArrayList;
public class 最长递增序列 {
static int[][] rect={
{97,47,56,36},
{35,57,41,13},
{89,36,98,75},
{25,45,26,17}
};
static ArrayList<String> al=new ArrayList<String>();
static ArrayList<String> longMax=new ArrayList<String>();
public static void main(String[] args){
for(int i=0;i<rect.length;i++)
for(int j=0;j<rect[0].length;j++){
seek(i,j);
al=new ArrayList<String>();
}
System.out.println(longMax);
}
public static void seek(int bx,int by){
al.add(rect[bx][by]+"");
if(al.size()>longMax.size())
longMax=new ArrayList(al);
for(int x=-1;x<=1;x++)
for(int y=-1;y<=1;y++)
if(0<=bx+x && 0<=by+y && bx+x<=3 && by+y<=3 && rect[bx][by]<rect[bx+x][by+y]){
ArrayList<String> temp=new ArrayList<String>(al);
seek(bx+x,by+y);
al=temp;
}
}
}
<pre name="code" class="html"><pre name="code" class="html">以下的代码将已经试过某一个网格的最长路径保存了下来,这样再次调用时就能够直接使用
import java.util.ArrayList;
public class 最长递增序列 {
static int[][] rect={
{97,47,56,36},
{35,57,41,13},
{89,36,98,75},
{25,45,26,17}
};
static ArrayList<Integer> al=new ArrayList<Integer>();
static ArrayList<Integer> longMax=new ArrayList<Integer>();
static ArrayList<Integer> partMax=new ArrayList<Integer>();
static int[][][] stoal=new int[rect.length][rect[0].length][rect.length*rect[0].length];
public static void main(String[] args){
for(int i=0;i<rect.length;i++)
for(int j=0;j<rect[0].length;j++){
seek(i,j);
memery(i,j);
al=new ArrayList<Integer>();
}
System.out.println(longMax);
}
public static void seek(int bx,int by){
if(stoal[bx][by][0]!=0){
for(int l=0;l<stoal[bx][by].length && stoal[bx][by][l]!=0;l++)
al.add(stoal[bx][by][l]);
if(al.size()>longMax.size())
longMax=new ArrayList(al);
if(al.size()>partMax.size())
partMax=new ArrayList(al);
return;
}
al.add(rect[bx][by]);
if(al.size()>longMax.size())
longMax=new ArrayList(al);
if(al.size()>partMax.size())
partMax=new ArrayList(al);
for(int x=-1;x<=1;x++)
for(int y=-1;y<=1;y++)
if(0<=bx+x && 0<=by+y && bx+x<=3 && by+y<=3 && rect[bx][by]<rect[bx+x][by+y]){
ArrayList<Integer> temp=new ArrayList<Integer>(al);
seek(bx+x,by+y);
al=temp;
}
}
public static void memery(int i,int j){
int len=partMax.size();
for(int k=0;k<len;k++)
stoal[i][j][k]=partMax.remove(0);
}
}