4
实验1:
1 #include <stdio.h> 2 #define N 4 3 #define M 2 4 5 void test1() { 6 int x[N] = {1, 9, 8, 4}; 7 int i; 8 9 10 printf("sizeof(x) = %d\n", sizeof(x)); 11 12 13 for (i = 0; i< N; ++i) 14 printf("%p: % d\n",&x[i], x[i]); 15 16 17 printf("x = %d\n", x); 18 } 19 20 void test2() { 21 int x[M][N] = {{1, 9, 8, 4},{2, 0, 4, 9}}; 22 int i,j; 23 24 25 printf("sizeof(x) = %d\n", sizeof(x)); 26 27 28 for(i = 0; i < M; ++i) 29 for(j = 0; j < N; ++j) 30 printf("%p: %d\n", &x[i][j], x[i][j]); 31 printf("\n"); 32 33 34 printf("x = %p\n", x); 35 printf("x[0] = %p\n", x[0]); 36 printf("x[1] = %p\n", x[1]); 37 printf("\n"); 38 } 39 40 int main() { 41 printf("测试1: int型一维数组\n"); 42 test1(); 43 44 printf("\n测试2: int型二维数组\n"); 45 test2(); 46 47 return 0; 48 }
实验2
1 #include <stdio.h> 2 #define N 100 3 4 5 void input(int x[], int n); 6 double compute(int x[], int n); 7 8 int main() { 9 int x[N]; 10 int n,i; 11 double ans; 12 13 while(printf("Enter n:"),scanf("%d", &n) != EOF) { 14 input(x, n); 15 ans + compute(x, n); 16 printf("ans = %.2f\n\n", ans); 17 } 18 19 return 0; 20 } 21 22 23 void input(int X[], int n) { 24 int i; 25 26 for(i = 0;i < n; ++i) 27 scanf("%d", &X[i]); 28 } 29 30 31 double compute(int x[], int n) { 32 int i,high, low; 33 double ans; 34 35 high = low = x[0]; 36 ans =0; 37 38 for(i = 0; i < n; ++i) { 39 ans += x[i]; 40 41 if(x[i] < low) 42 high = x[i]; 43 else if(x[i] < low) 44 low = x[i]; 45 } 46 47 ans = (ans - high - low)/(n-2); 48 49 return ans; 50 }
实验3:
1 #include <stdio.h> 2 #define N 100 3 4 5 void output(int x[][N], int n); 6 void init(int x[][N], int n, int value); 7 8 int main() { 9 int x[N][N]; 10 int n, value; 11 12 while(printf("Enter n and value:"),scanf("%d%d", &n, &value) != EOF) { 13 init(x, n, value); 14 output(x, n); 15 printf("\n"); 16 } 17 18 19 return 0; 20 } 21 22 void output(int x[][N], int n) { 23 int i, j; 24 25 for(i = 0; i < n; ++i) { 26 for(j = 0; j < n; ++j) 27 printf("%d ", x[i][j]); 28 printf("\n"); 29 } 30 } 31 32 void init(int x[][N], int n, int value) { 33 int i, j; 34 35 for(i = 0; i < n; ++i) 36 for(j = 0; j < n; ++j) 37 x[i][j] = value; 38 }
第一维
输入i*j的数据
输出n*n的数据
实验5
1 #include <stdio.h> 2 #define N 100 3 4 void input(int x[],int n); 5 double median(int x[],int n); 6 void sort(int x[], int n); 7 8 int main() { 9 int x[N]; 10 int n; 11 double ans; 12 13 while(printf("Enter n: "), scanf("%d", &n) != EOF) { 14 input(x, n); 15 ans = median(x, n); 16 printf("ans = %g\n\n", ans); 17 } 18 19 return 0; 20 } 21 22 void input(int x[], int n) { 23 int i; 24 25 for(i = 0; i < n; ++i) 26 scanf("%d", &x[i]); 27 } 28 29 double median(int x[],int n){ 30 sort(x,n); 31 if(n%2==0){ 32 return (x[n/2]+x[n/2-1])/2.0; 33 } 34 else { 35 return (x[n/2]); 36 } 37 } 38 39 void sort(int x[], int n) { 40 int i,j; 41 for ( i = 0; i < n - 1; i++) { 42 for ( j = 0; j < n - i - 1; j++) { 43 if (x[j] > x[j + 1]) { 44 int temp = x[j]; 45 x[j] = x[j + 1]; 46 x[j + 1] = temp; 47 } 48 } 49 } 50 }
实验6
1 #include <stdio.h> 2 #define N 100 3 4 void dec_to_n(int x, int n); 5 6 int main() { 7 int x; 8 while(printf("输入十进制整数: "), scanf("%d", &x) != EOF) { 9 dec_to_n(x, 2); 10 dec_to_n(x, 8); 11 dec_to_n(x, 16); 12 printf("\n"); 13 } 14 15 return 0; 16 } 17 18 void dec_to_n(int x,int n){ 19 int a[N],i,j=0; 20 for(i=x;i!=0;i/=n){ 21 a[j]=x%n; 22 x/=n; 23 j++; 24 } 25 for(i=j-1;i>=0;i--){ 26 if(a[i]%n>9) 27 printf("%c",a[i]-10+'A'); 28 else 29 printf("%c",a[i]+'0'); 30 } 31 printf("\n"); 32 }
实验7
1 #include<stdio.h> 2 #define N 100 3 4 void input(int x[][N],int n); 5 void output(int x[][N],int n); 6 int is_magic(int [][N],int n); 7 8 int main(){ 9 int x[N][N]; 10 int n; 11 12 while(printf("输入:"),scanf("%d",&n)!=EOF){ 13 printf("输入方阵:\n"); 14 input(x,n); 15 16 printf("输出方阵:\n"); 17 output(x,n); 18 19 if(is_magic(x,n)) 20 printf("是魔方矩阵\n\n"); 21 else 22 printf("不是魔方矩阵\n\n"); 23 } 24 return 0; 25 } 26 27 void input(int x[][N],int n){ 28 int i,j; 29 30 for(i=0;i<n;++i){ 31 for(j=0;j<n;++j) 32 scanf("%d",&x[i][j]); 33 } 34 } 35 36 void output(int x[][N],int n){ 37 int i,j; 38 39 for(i=0;i<n;++i){ 40 for(j=0;j<n;++j) 41 printf("%4d",x[i][j]); 42 43 printf("\n"); 44 } 45 } 46 47 int is_magic(int x[][N],int n){ 48 int i,j; 49 int sum1,sum2,sum3=0,sum4=0; 50 51 52 for(i=0;i<n;++i){ 53 sum1=0,sum2=0; 54 55 for(j=0;j<n;++j){ 56 sum1+=x[i][j]; 57 sum2+=x[j][i]; 58 } 59 60 if(sum1!=sum2) 61 return 0; 62 } 63 64 for(i=0;i<n;++i){ 65 sum3+=x[i][i]; 66 sum4+=x[i][n-i-1]; 67 } 68 69 if(sum3!=sum4) 70 return 0; 71 72 return 1; 73 }