[刷题] 1002 写出这个数 (20分)
要求
- 读入一个正整数 n,计算其各位数字之和,用汉语拼音写出和的每一位数字
输入格式
- 每个测试输入包含 1 个测试用例,即给出自然数 n 的值。这里保证 n 小于 1
输出格式
- 在一行内输出 n 的各位数字之和的每一位,拼音数字间有 1 空格,但一行中最后一个拼音数字后没有空格
输入样例
1234567890987654321123456789
输出样例
yi san wu
实现
- java
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String[] strings = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; String s = in.nextLine(); char[] chars = s.toCharArray(); int sum = 0; for(char c:chars){ int x = c - '0'; sum += x; } String sumS = String.valueOf(sum); char[] charSum = sumS.toCharArray(); StringBuilder StringBuilder = new StringBuilder(); for(char c:charSum){ int x = c - '0'; StringBuilder.append(strings[x]+" "); } StringBuilder.deleteCharAt(StringBuilder.length()-1); System.out.println(StringBuilder.toString()); } }
- c++
#include<iostream> #include<string> using namespace std; int main(){ string str; getline(cin,str); int sum=0; for(int i = 0; i < str.size(); i ++) sum += str[i] - '0'; string a[10] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; string re = to_string(sum); for( int i = 0 ; i < re.size() - 1 ; i ++ ) cout << a[re[i] - '0'] << " "; cout << a[[re.size()-1]-'0']; }