抄写第九章例题

例9.1

#include<stdio.h>
#include<stdlib.h>
main()
{struct Student
{long int num;
char name[20];
char sex;
char addr[20];
}a={10101,"li lin",'M',"123 beijing Road"};
printf("NO.;%ld\nname:%s\nsex:%c\naddress:%s\n",a.num,a.name,a.sex,a.addr);
return 0;
}

NO.;10101
name:li lin
sex:M
address:123 beijing Road

--------------------------------
Process exited after 0.434 seconds with return value 0
请按任意键继续. . .

例9.2

#include<stdio.h>
#include<stdlib.h>
int main()
{struct Student
 {int num;
char name[20];
float score;
}; 
struct Student student1={10101,"wang",89};
struct Student student2={10103,"ling",98};
if(student1.score>student2.score)
printf("%d,%s,%f",student1.num,student1.name,student1.score);
else if(student1.score<student2.score)
printf("%d,%s,%f",student2.num,student2.name,student2.score);
else
{
printf("%d,%s,%f",student1.num,student1.name,student1.score);
printf("%d,%s,%f",student2.num,student2.name,student2.score);
}
return 0;
}

10103,ling,98.000000
--------------------------------
Process exited after 0.3591 seconds with return value 0
请按任意键继续. . .

例9.3

#include<string.h>
#include<stdio.h>
struct Person//声明结构体类型 struct person 
{char name[20];//候选人姓名 
int count;//候选人的票数 
 } leader[3]={"li",0,"zhang",0,"Sun",0};//定义结构体数组并初始化 
 int main()
 {int i,j;
 char leader_name[20];
 for(i=1;i<=10;i++)
 {scanf("%s",leader_name);//输入所选的候选人姓名 
 for(j=0;j<3;j++)
 if(strcmp(leader_name,leader[j].name)==0)leader[j].count++;
 }
 printf("\nResult:\n");
 for(i=0;i<3;i++)
 printf("%5s:%d\n",leader[i].name,leader[i].count);
 return 0;
  }

 Li
Li
Sun
Zhang
Zhabg
Sun
Li
Sun
Zhang
Li

Result:
   li:0
zhang:0
  Sun:3

--------------------------------
Process exited after 85.36 seconds with return value 0
请按任意键继续. . .

例9.4

#include<stdio.h>
#include<stdlib.h> 
struct Student//声明结构体类型 struct person 
{
int num;
char name[20];
float score;
};
int main()
{
struct Student stu[5]={{10101,"zhang",78},{10103,"wang",98},{10106,"li",86},{10108,"ling",73},{10110,"sun",100}};//定义结构体数组并初始化
struct Student temp;
const int n=5;
int i,j,k;//定义常变量n 
printf("the order is:\n");
for(i=0;i<n-1;i++)
{k=i;
for(j=i+1;j<n;j++)
if(stu[j].score>stu[k].score)
k=j;
temp=stu[k];stu[k]=stu[i];stu[i]=temp;    //stu[k]和stu[i]元素互换 
}
for(i=0;i<n;i++)
printf("%d,%s,%d",stu[i].num,stu[i].name,stu[i].score);
printf("\n");
return 0;
}

the order is:
10110,sun,010103,wang,010106,li,010101,zhang,010108,ling,0

--------------------------------
Process exited after 0.2652 seconds with return value 0
请按任意键继续. . .

例9.5

#include<stdio.h>
#include<stdlib.h> 
struct Student//声明结构体类型 struct person 
{
int num;
char name[20];
char sex;
int age;
};
struct Student stu[3]={{10101,"zhang",'M',78},{10103,"wang",'M',98},{10106,"li",'M',86}};//定义结构体数组并初始化 
main()
{struct Student *p;//定义指向struct student类型数据的指针变量p 
printf("NO.Name   sex age\n");
for(p=stu;p<stu+3;p++)
printf("%d,%s,%c,%d",p->num,p->name,p->sex,p->age);
return 0;
}

NO.Name   sex age
10101,zhang,M,7810103,wang,M,9810106,li,M,86
--------------------------------
Process exited after 0.4277 seconds with return value 0
请按任意键继续. . .

例9.6

#include<stdio.h>
#include<string.h>
main()
{struct Student
{long num;
char name[20];
char sex;
float score;
};
struct Student stu_1;//定义struct student类型的变量stu_1 
struct Student *p;//定义指向struct student类型数据的指针变量p 
p=&stu_1;//p指向stu—1 
stu_1.num=10101;//对结构体变量的成员赋值 
strcpy(stu_1.name,"li lin");//用字符串复制函数给stu_1.name赋值 
stu_1.sex='M';
stu_1.score=89;
printf("NO.:%ld\nname:%s\nsex:%c\nscore:%d\n",stu_1.num,stu_1.name,stu_1.sex,stu_1.score);
printf("NO.:%ld\nname:%s\nsex:%c\nscore:%d\n",(*p).num,(*p).name,(*p).sex,(*p).score);
return 0;
}

NO.:10101
name:li lin
sex:M
score:0
NO.:10101
name:li lin
sex:Mscore:0

--------------------------------
Process exited after 0.4299 seconds with return value 0
请按任意键继续. . .

例9.7

#include<stdio.h>
#define N 3    //学生数为3 
struct Student//声明结构体类型 struct person 
{
int num;
char name[20];
float score[3];//三门课成绩 
float aver;//平均成绩 
};
int main()
{void input(struct Student stu[]);
struct Student max(struct Student stu[]);
void print(struct Student stu[]);
struct Student stu[N],*p=stu;//定义结构体数组和指针 
input(p);//调用input函数 
print(max(p));//调用print函数，以max函数的返回值作为实参 
return 0;
}
void input(struct Student stu[])
{int i;
printf("请输入个学生的信息：学号，姓名，三门课成绩：\n");
for(i=0;i<N;i++)
{scanf("%d,%s,%f,%f,%f",&stu[i].num,stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]);//输入数据 
stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0;//求平均值 
}
}
struct Student max(struct Student stu[])
{int i,m=0;//用m存放成绩最高的学生在数组中的序号 
for(i=0;i<N;i++)
if(stu[i].aver>stu[m].aver)m=i;//找出平均成绩最高的学生在数组中的序号 
return stu[m];//返还值包含该生信息的结构体元素 
}
void print(struct Student stud)
{printf("\n成绩最好的学生是：\n");
printf("学号：%d\姓名：%s\n三门课成绩：%5.1f,%5.1f,%5.1f\n平均成绩：%6.2f，stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2],stud.aver");
}

请输出各学生的信息：学号、姓名、三门课成绩：
10101 li 78 89 98
10103 wang 98.5 87 69
10106 sun 88 76.5 89

成绩最高的学生是:
学号：10101
姓名:10485108
三门课成绩: 78.0, 89.0, 98.0
平均成绩: 88.33

--------------------------------
Process exited after 99.13 seconds with return value 0
请按任意键继续. . 

总结：通过本次作业，觉得编程要多练习，熟能生巧，抄写时出现了忘记加等号等的细节错误，弄了一天，学到了很多。