JAVA List<Map<String, Object>> sort 多个排序写法

 

基本方法

    /**
     * 排序=
     *
     * @param list
     * @param sort_key
     * @return
     */
    public static List<Map<String, Object>> sort(List<Map<String, Object>> list, String sort_key,Boolean asc, String sort_key2,Boolean asc2) {


        Collections.sort(list, (map1, map2) -> {
            Double totalprice1 = map1 == null ? 0.0 : Double.parseDouble(map1.get(sort_key).toString());
            Double totalprice2 = map2 == null ? 0.0 : Double.parseDouble(map2.get(sort_key).toString());
            int i =0;
            i=asc?totalprice1.compareTo(totalprice2):totalprice2.compareTo(totalprice1);
            if (i != 0)
                return i;
            Double d1 = Double.parseDouble(map1.get(sort_key2).toString());
            Double d2 = Double.parseDouble(map2.get(sort_key2).toString());
            return asc2?d1.compareTo(d2):d2.compareTo(d1);

        });
        return list;
    }

 

写个demo测试一下

 static void testSort() {
        List<Map<String, Object>> list = new ArrayList<>();
        Map<String, Object> item0 = new HashMap<>();
        item0.put("price", 50);
        item0.put("tax", 3);
        item0.put("name", "item0");

        Map<String, Object> item1 = new HashMap<>();
        item1.put("price", 100.0);
        item1.put("tax", 1);
        item1.put("name", "item1");
        Map<String, Object> item2 = new HashMap<>();
        item2.put("price", 50.0);
        item2.put("tax", 1);
        item2.put("name", "item2");

        Map<String, Object> item3 = new HashMap<>();
        item3.put("price", 150.0);
        item3.put("tax", 3);
        item3.put("name", "item3");

        list.add(item0);
        list.add(item1);
        list.add(item2);
        list.add(item3);
        List<Map<String, Object>> result = sort(list,  "tax",true,"price",true);

        System.out.println(result);

        List<Map<String, Object>> result2 = sort(list,  "price",true,"tax",true);
        System.out.println(result2);
    }

 

打印结果

[{price=50.0, name=item2, tax=1}, {price=100.0, name=item1, tax=1}, {price=50, name=item0, tax=3}, {price=150.0, name=item3, tax=3}]
[{price=50.0, name=item2, tax=1}, {price=50, name=item0, tax=3}, {price=100.0, name=item1, tax=1}, {price=150.0, name=item3, tax=3}]

 

结果符合

 

又多了一项无用的技能