题解:大多数做法是利用循环相除,取余。我是将将A+B传入f函数,利用递归实现D进制的输出 题目地址:https://www.nowcoder.com/questionTerminal/a2063993dd424f9cba8246a3cf8ef445 Read More
posted @ 2019-10-28 21:09 LifeRunningError Views(150) Comments(0) Diggs(0) Edit
思路:每接受一个字符,便统计一次即可 题目地址:https://www.nowcoder.com/questionTerminal/a2063993dd424f9cba8246a3cf8ef445 Read More
posted @ 2019-10-28 20:44 LifeRunningError Views(148) Comments(0) Diggs(0) Edit