剑指offer-二进制中1的个数

题目地址：https://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8?tpId=13&&tqId=11164&rp=1&ru=/activity/oj&qru=/ta/coding-interviews/question-ranking

n=n&(n-1);

核心代码

class Solution {
public:
     int  NumberOf1(int n) {
         int res=0;
         while(n!=0){
             res++;
             n=n&(n-1);
         }
         return res;
     }
};