摘要: res.groupby(['customer_id'])['project_name'].apply(lambda x:', '.join(x)).reset_index() x.groupby(['sa'])['daList'].apply(lambda x:np.concatenate(list 阅读全文
posted @ 2020-02-06 18:22 cup_leo 阅读(1161) 评论(0) 推荐(0) 编辑