摘要:
class Solution { public: void merge(vector& nums1, int m, vector& nums2, int n) { int k = nums1.size() - m; for(int i=0;i < k;i++){ nums1.pop_back(); } ... 阅读全文
摘要:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* p... 阅读全文