Conversions(水)
Conversions
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1054 Accepted Submission(s): 618
Problem Description
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:
![](http://acm.hdu.edu.cn/data/images/C105-1002-1.JPG)
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification
for the converted value.
Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l
Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
Source
Recommend
linle
1 #include <iostream> 2 #include <string> 3 #include <cstdio> 4 #include <cmath> 5 #include <cstring> 6 #include <algorithm> 7 #define LL long long 8 #define maxi 2147483647 9 #define maxl 9223372036854775807 10 #define dg cout << "Here!" << endl; 11 using namespace std; 12 13 int main() 14 { 15 int n, t = 1; 16 double a; 17 string s; 18 cin >> n; 19 while(n--) 20 { 21 cin >> a >> s; 22 if(s == "kg") 23 printf("%d %.4lf lb\n", t++, a * 2.2046); 24 else if(s == "lb") 25 printf("%d %.4lf kg\n", t++, a * 0.4536); 26 else if(s == "l") 27 printf("%d %.4lf g\n", t++, a * 0.2642); 28 else if(s == "g") 29 printf("%d %.4lf l\n", t++, a * 3.7854); 30 } 31 return 0; 32 }