音乐研究

 

题目大意，给你一个长度为n的数组a，和一个长度为m的b数组，让你求出b数组中长度为n的数组使得SUM(a[i] - b[i])2 最小；

题解：这是一道水题，简单的暴力枚举就好了

接下来是代码

#include<stdio.h>
#include<string.h>
#include<math.h>
#include<iostream>
#include<algorithm>
#include<queue>
#include<vector>
#define ll long long
using namespace std;

const int inf = 0x3f3f3f3f;
const int maxn = 100010;
int a[maxn];
int b[maxn];
int main()
{
    int n;
    cin >> n;
    for (int i = 1; i <= n; i++)
    {
        cin >> a[i];
    }
    int m;
    cin >> m;
    for (int j = 1; j <= m; j++)
    {
        cin >> b[j];
    }
    int minx = inf;
    for (int j = n; j <= m; j++)
    {
        int sum = 0;
        for (int i = j,k=n; i >= j - n + 1; i--,k--)
        {
            sum += pow(b[i] - a[k], 2);
        }
        minx = min(sum, minx);
    }
    cout << minx << endl;
}