Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
这个题目只要注意如果字符串以‘ ’结尾的情况就行了例如"Hello World "的返回值也是5
class Solution { public: int lengthOfLastWord(string s) { size_t length=0; bool tag=false; for(int i=s.size()-1;i>=0;--i) { if(s[i]!=' ') { tag=true; ++length; } if(s[i]==' '&&tag)return length; } return length; } };