You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
很明显看出这是个斐波那契数列,但是我们一般不用递归的方法,而采用循环来求解
class Solution { public: int climbStairs(int n) { if (n < 1)return 0; vector<int> vec(n+1, 0); vec[0] = 1;vec[1] = 1; for (int i = 2;i <= n;++i) { vec[i] = vec[i - 1] + vec[i - 2]; } return vec[n]; } };