Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
题目:看看两个单词是否同构。这是一个明显的hash表的问题,但是要注意没有两个字母对应着一个字母,但是同一个字母可以对着自己本身
class Solution { public: bool isIsomorphic(string s, string t) { map<char, char> chChMap,chChMap2; for (unsigned i = 0;i < s.size();++i) { if (chChMap.find(s[i]) == chChMap.end()) chChMap[s[i]] = t[i]; else if (t[i] != chChMap[s[i]]) return false; if (chChMap2.find(t[i]) == chChMap2.end()) chChMap2[t[i]] = s[i]; else if (s[i] != chChMap2[t[i]]) return false; } return true; } };