[UNCTF2020]BetterCpu WriteUp

这题不同前一题虚拟机ezvm一样,指令很多而且复杂,需要通过写文档和脚本来化简过程。

 直接丢进IDA7.2(如果使用IDA7.0则虚拟机的emulator部分会分析出错)查看。

   进入main函数后按F5反编译,再进入ezvm::ezvm()里看构造函数的初始化,因为出题人已经给了符号表,所以捋清整个控制流其实是不难的(比赛时没做出来,问就是没加载符号表和不会写脚本)。&v1 + 4的地址就是局部变量enc_flag的地址,故unk_409020就是加密后的flag。

怎么加载符号表?就是进入IDA7.2时会弹出一个关于DWARF debug informa的对话框,选Yes就行了 。 

 然后进入ezvm::run(),里面一大段switch显然就是虚拟机的emulator部分,而且显然是个栈式虚拟机(什么是堆栈虚拟机和寄存器虚拟机?)如果还不清楚,后面写脚本生成的伪汇编代码就会看的更清楚。

需要注意的是,这个虚拟机栈的sp并不是指向栈的第一个元素,而是指向第一个元素的前面一个元素。

下面是虚拟机机器码的文档(其实也可以不用写)。

BetterCpu Virtual Machine Instructment

9bytes
0xEu
cmp rflag,1
je $+idata

9bytes
0xFu
cmp rflag,1
je $-idata

0x10u
push reg

0x11u
pop reg

0x12u
pop mem[reg]

0x13u
push mem[reg]

9bytes
0x20u
mov reg,idata

0x21u
mov reg,getchar()

0x22u
putchar(reg)

0x30u
sadd

0x31u
ssub

0x32u
sxor

0x33u
slhs

0x34u
srhs

0x40u
scmp

0x80u
return

其中sdd,ssub,sxor,scmp是我自己编的指令方便写脚本,读者可以对照反编译结构自行理解。

下面就可以写脚本将机器码翻译成汇编代码了。

codes =[
  0x20, 0x57, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x65, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x31, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x63, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x30, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x6D, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x65, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x0A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x50, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x6C, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x65, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x61, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x73, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x65, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x49, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x6E, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x50, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x75, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x74, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x3A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x0A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 
  0x12, 0x21, 0x10, 0x20, 0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x10, 0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x13, 0x30, 0x11, 0x12, 0x20, 0x01, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x20, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x30, 0x12, 0x20, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x20, 0x2C, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x40, 0x0F, 
  0x44, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x20, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x12, 0x20, 
  0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x20, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x30, 
  0x11, 0x13, 0x20, 0x66, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x10, 0x30, 0x20, 0x36, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x10, 0x32, 0x20, 0x42, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x10, 0x31, 0x20, 0x00, 0x01, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x10, 0x20, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x13, 0x30, 0x11, 0x12, 0x20, 0x01, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x20, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x30, 0x12, 
  0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 
  0x20, 0x2C, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 
  0x40, 0x0F, 0x7A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 
  0x12, 0x20, 0x00, 0x01, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x10, 0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x13, 0x30, 0x11, 0x13, 0x20, 0x50, 0x01, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x10, 0x20, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x13, 0x30, 0x11, 0x13, 0x40, 0x0E, 0x98, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x20, 0x01, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x20, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x30, 0x12, 0x20, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x13, 0x20, 
  0x2C, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x10, 0x40, 
  0x0F, 0x63, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x20, 
  0x53, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x75, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x63, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x63, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x65, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x73, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x73, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x21, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x20, 
  0x0A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 0x80, 
  0x20, 0x46, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x41, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x49, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x4C, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x20, 0x0A, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x22, 
  0x80, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
  0x00, 0x00, 0x00, 0x00, 0x00, 0x00
]

fp = open('./codes.asm','wb')
def getQword(i):
    return (codes[i+1] + (codes[i+2] << 8) + (codes[i+3] << 16) + (codes[i+4] << 32) + (codes[i+5] << 8) +
    (codes[i+6] << 40) + (codes[i+7] << 48)  + (codes[i+8] << 56))

i = 0
while i < len(codes):
    if codes[i] == 0xE:
        fp.write(b"cmp rflag,1\nje $ + "+ hex(getQword(i)).encode() + b"\n")
        i+=9
    elif codes[i] == 0xF:
        fp.write(b"cmp rflag,1\nje $ - "+ hex(getQword(i)).encode() + b"\n")
        i+=9
    elif codes[i] == 0x10:
        fp.write(b"push reg\n")
        i+=1
    elif codes[i] == 0x11:
        fp.write(b"pop reg\n")
        i+=1
    elif codes[i] == 0x12:
        fp.write(b"pop mem[reg]\n")
        i+=1
    elif codes[i] == 0x13:
        fp.write(b"push mem[reg]\n")
        i+=1
    elif codes[i] == 0x20:
        fp.write(b"mov reg," + hex(getQword(i)).encode()+ b"\n")
        i+=9
    elif codes[i] == 0x21:
        fp.write(b"mov reg,getchar()\n")
        i+=1
    elif codes[i] == 0x22:
        fp.write(b"putchar(reg)\n")
        i+=1
    elif codes[i] == 0x30:
        fp.write(b"sadd\n")
        i+=1
    elif codes[i] == 0x31:
        fp.write(b"ssub\n")
        i+=1
    elif codes[i] == 0x32:
        fp.write(b"sxor\n")
        i+=1
    elif codes[i] == 0x33:
        fp.write(b"slhs\n")
        i+=1
    elif codes[i] == 0x34:
        fp.write(b"srhs\n")
        i+=1
    elif codes[i] == 0x40:
        fp.write(b"scmp\n")
        i+=1
    elif codes[i] == 0x80:
        fp.write(b"end\n")
        break

生成的伪汇编代码如下:

mov reg,0x57
putchar(reg)
mov reg,0x65
putchar(reg)
mov reg,0x31
putchar(reg)
mov reg,0x63
putchar(reg)
mov reg,0x30
putchar(reg)
mov reg,0x6d
putchar(reg)
mov reg,0x65
putchar(reg)
mov reg,0xa
putchar(reg)
mov reg,0x50
putchar(reg)
mov reg,0x6c
putchar(reg)
mov reg,0x65
putchar(reg)
mov reg,0x61
putchar(reg)
mov reg,0x73
putchar(reg)
mov reg,0x65
putchar(reg)
mov reg,0x20
putchar(reg)
mov reg,0x49
putchar(reg)
mov reg,0x6e
putchar(reg)
mov reg,0x50
putchar(reg)
mov reg,0x75
putchar(reg)
mov reg,0x74
putchar(reg)
mov reg,0x3a
putchar(reg)
mov reg,0xa
putchar(reg)
;print Welc0me Input


mov reg,0x0
push reg
pop mem[reg]


;将UserInput字符串放入memory+0x100处
loop_1:
mov reg,getchar()
push reg
mov reg,0x100
push reg
mov reg,0x0
push mem[reg]
;stack men[reg] 0x100 UserInput
sadd
pop reg
pop mem[reg]
mov reg,0x1
push reg
mov reg,0x0
push mem[reg]
sadd
pop mem[reg]
mov reg,0x0
push mem[reg]
mov reg,0x2c
push reg
scmp
cmp rflag,1 ;循环够0x2C次
je loop_1



mov reg,0x0
push reg
pop mem[reg]



loop_2:
mov reg,0x100
push reg
mov reg,0x0
push mem[reg]
sadd
pop reg
push mem[reg];pointer to UserInput
mov reg,0x66
push reg
sadd
mov reg,0x36
push reg
sxor
mov reg,0x42
push reg
ssub
mov reg,0x100
push reg
mov reg,0x0
push mem[reg]
sadd
pop reg
pop mem[reg]
;enc_flag[i] == (UserInput[i] + 0x66)^0x36-0x42
mov reg,0x1
push reg
mov reg,0x0
push mem[reg]
sadd
pop mem[reg]
mov reg,0x0
push mem[reg]
mov reg,0x2c
push reg
scmp
cmp rflag,1
je loop_2



mov reg,0x0
push reg
pop mem[reg]
mov reg,0x100
push reg
mov reg,0x0
push mem[reg]
sadd
pop reg
push mem[reg]
mov reg,0x150
push reg
mov reg,0x0
push mem[reg]
sadd
pop reg
push mem[reg]
scmp
cmp rflag,1
je $ + 0x98
mov reg,0x1
push reg
mov reg,0x0
push mem[reg]
sadd
pop mem[reg]
mov reg,0x0
push mem[reg]
mov reg,0x2c
push reg
scmp
cmp rflag,1
je $ - 0x63


;print Success
mov reg,0x53
putchar(reg)
mov reg,0x75
putchar(reg)
mov reg,0x63
putchar(reg)
mov reg,0x63
putchar(reg)
mov reg,0x65
putchar(reg)
mov reg,0x73
putchar(reg)
mov reg,0x73
putchar(reg)
mov reg,0x21
putchar(reg)
mov reg,0xa
putchar(reg)
end

加密过程很简单,注释已经写好在伪汇编代码里了,直接写脚本得flag:

#include<iostream>
#include<string>
using namespace std;

int enc_flag[]= {171,160,189,170,184,149,74,86,87,77,177,72,67,177,183,173,177,92,187,170,170,187,172,177,74,182,175,160,177,71,66,92,121,173,177,91,107,177,108,104,107,94,147,4,0};
string flag;
int main(void){
  for(int i = 0;i < 0x2c; ++i){
    flag += ((enc_flag[i]+0x42)^0x36)-0x66;
  }
  cout << flag << endl;
  return 0;
}

flag: unctf{THIS_VM_is_Better_Than_YLB's_E5_2650}

posted @ 2020-11-18 16:40  CSULuyao  阅读(240)  评论(3编辑  收藏  举报