【简单】罗马数字转整数
https://leetcode-cn.com/problems/roman-to-integer/
能比较快想到的一个方法:
public class RomanToInt { public static int romanToInt(String s) { int ret = 0; Map<String,Integer> map = new HashMap<>(); Map<String,Integer> mapCombine = new HashMap<>(); map.put("I",1); map.put("V",5); map.put("X",10); map.put("L",50); map.put("C",100); map.put("D",500); map.put("M",1000); mapCombine.put("IV",4); mapCombine.put("IX",9); mapCombine.put("XL",40); mapCombine.put("XC",90); mapCombine.put("CD",400); mapCombine.put("CM",900); char[] charArr = s.toCharArray(); int i = 0; if(s.length() == 1){ ret += map.get(String.valueOf(charArr[0])); }else{ while(i < s.length()){ if((i+1) >= s.length()) { ret += map.get(String.valueOf(charArr[i])); break; } if(mapCombine.containsKey(String.valueOf(charArr[i]) + String.valueOf(charArr[i+1]))){ ret += mapCombine.get(String.valueOf(charArr[i]) + String.valueOf(charArr[i+1])); i=i+2; }else{ ret += map.get(String.valueOf(charArr[i])); i++; } } } return ret; } public static void main(String[] args){ System.out.println(romanToInt("III")); System.out.println(romanToInt("IV")); System.out.println(romanToInt("IX")); System.out.println(romanToInt("LVIII")); System.out.println(romanToInt("MCMXCIV")); } }
网上看到还有一个更直观的解法
int ret = 0; Map<String,Integer> map = new HashMap<>(); map.put("I",1); map.put("V",5); map.put("X",10); map.put("L",50); map.put("C",100); map.put("D",500); map.put("M",1000); map.put("O",4); map.put("P",9); map.put("Q",40); map.put("R",90); map.put("S",400); map.put("T",900); s = s.replaceAll("IV","O"); s = s.replaceAll("IX","P"); s = s.replaceAll("XL","Q"); s = s.replaceAll("XC","R"); s = s.replaceAll("CD","S"); s = s.replaceAll("CM","T"); char[] charArr = s.toCharArray(); for(char c : charArr){ ret += map.get(String.valueOf(c)); } return ret;