js获取url参数

js获取url参数

一、

function getUrl(name) {
    var reg = new RegExp("(\\?|\&)" + name + "=([^&]*)(\&|$)", "i");
    var r = window.location.href.match(reg);
    if (r != null) return unescape(r[2]); return null;
}

二、

function GetRequest() {
   var url = location.search; //获取url中"?"符后的字串
   var theRequest = new Object();
   if (url.indexOf("?") != -1) {
      var str = url.substr(1);
      strs = str.split("&");
      for(var i = 0; i < strs.length; i ++) {
         theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
      }
   }
   return theRequest;
}

 

posted @ 2014-12-04 21:02  cssfirefly  阅读(451)  评论(0编辑  收藏  举报
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