poj 2299 求逆序数
1 #include <iostream> 2 const int MAX = 500000; 3 int a[MAX]; 4 int swap[MAX]; //临时数组 5 int n; //数组a的长度 6 __int64 result; //数组a中的逆序数 7 8 //归并两个已经有序的段:a[low]—a[mid]和a[mid+1]—a[high],使得a[low]—a[high]有序。 9 void merge(int low, int mid, int high) 10 { 11 int i = low; 12 int j = mid + 1; 13 int m = 0; 14 while(i <= mid && j <= high) 15 { 16 if(a[i] <= a[j]) 17 { 18 swap[m++] = a[i]; 19 i++; 20 } 21 else 22 { 23 swap[m++] = a[j]; 24 j++; 25 result += mid - i + 1; 26 } 27 } 28 while(i <= mid) 29 { 30 swap[m++] = a[i]; 31 i++; 32 } 33 while(j <= mid) 34 { 35 swap[m++] = a[j]; 36 j++; 37 } 38 for(i = 0; i < m; i++) 39 a[low + i] = swap[i]; 40 } 41 42 //归并排序:对a[low]—a[high]进行归并排序。 43 void mergeSort(int low, int high) 44 { 45 int mid; 46 if(low < high) 47 { 48 mid = (low + high) /2; 49 mergeSort(low, mid); 50 mergeSort(mid + 1, high); 51 merge(low, mid, high); 52 } 53 } 54 55 int main() 56 { 57 int i; 58 while(true) 59 { 60 scanf("%d",&n); 61 if(n == 0) break; 62 result = 0; 63 for(i = 0; i < n; i++) 64 scanf("%d",a+i); 65 mergeSort(0, n-1); 66 printf("%I64d\n",result); 67 } 68 return 0; 69 }