hdu 1021 Fibonacci Again(找规律)

http://acm.hdu.edu.cn/showproblem.php?pid=1021

Fibonacci Again

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 29201    Accepted Submission(s): 14148

Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

Output

Print the word "yes" if 3 divide evenly into F(n).
Print the word "no" if not.

 

Sample Input

0 1 2 3 4 5

 

Sample Output

no no yes no no no

 

Author

Leojay

 

思路：

题意：以7 11 开始的类似斐波拉契数列中能被3整除的输出yes  否则输出no

不解释 怒找一规律

 

上代码：

#include<iostream>
#include<stdio.h>
#include<string.h>

using namespace std;

int main()
{
    int n;
    while(~scanf("%d",&n))
    {
        if((n-2)%4==0)  puts("yes");
        else puts("no");
    }
    return 0;
}