POJ1579 Function Run Fun

Function Run Fun

Time Limit: 1000ms
Memory Limit: 10000KB
This problem will be judged on PKU. Original ID: 1579
64-bit integer IO format: %lld      Java class name: Main
 
We all love recursion! Don't we? 

Consider a three-parameter recursive function w(a, b, c): 

if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns: 


if a > 20 or b > 20 or c > 20, then w(a, b, c) returns: 
w(20, 20, 20) 

if a < b and b < c, then w(a, b, c) returns: 
w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c) 

otherwise it returns: 
w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1) 

This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion. 
 

Input

The input for your program will be a series of integer triples, one per line, until the end-of-file flag of -1 -1 -1. Using the above technique, you are to calculate w(a, b, c) efficiently and print the result.
 

Output

Print the value for w(a,b,c) for each triple.
 

Sample Input

1 1 1
2 2 2
10 4 6
50 50 50
-1 7 18
-1 -1 -1

Sample Output

w(1, 1, 1) = 2
w(2, 2, 2) = 4
w(10, 4, 6) = 523
w(50, 50, 50) = 1048576
w(-1, 7, 18) = 1

Source

 
解题:一个寒假没写代码了啊。。。。。。。先找下感觉啊。。。
 
 1 /*
 2 @author: Lev
 3 @date:
 4 */
 5 #include <iostream>
 6 #include <cstdio>
 7 #include <cmath>
 8 #include <cstring>
 9 #include <string>
10 #include <cstdlib>
11 #include <algorithm>
12 #include <map>
13 #include <set>
14 #include <queue>
15 #include <climits>
16 #include <deque>
17 #include <sstream>
18 #include <fstream>
19 #include <bitset>
20 #include <iomanip>
21 #define LL long long
22 #define PI acos(-1)
23 using namespace std;
24 int dp[30][30][30];
25 int go(int a,int b,int c) {
26     if(a <= 0 || b <= 0 || c <= 0) return 1;
27     if(a > 20 || b > 20 || c > 20) return go(20,20,20);
28     if(dp[a][b][c]) return dp[a][b][c];
29     if(a < b && b < c) dp[a][b][c] = go(a,b,c-1)+go(a,b-1,c-1)-go(a,b-1,c);
30     else dp[a][b][c] = go(a-1, b, c) + go(a-1, b-1, c) + go(a-1, b, c-1) - go(a-1, b-1, c-1);
31     return dp[a][b][c];
32 }
33 int main() {
34     memset(dp,0,sizeof(dp));
35     int a,b,c;
36     while(~scanf("%d %d %d",&a,&b,&c)) {
37         if(a == -1 && b == -1 && c == -1) break;
38         printf("w(%d, %d, %d) = %d\n",a,b,c,go(a,b,c));
39     }
40     return 0;
41 }
View Code

 

posted @ 2015-03-06 20:48  狂徒归来  阅读(132)  评论(0编辑  收藏  举报