数据库Mark.2
摘要：
select count(*) as count,DATE_SUB('2016-10-04',INTERVAL regDay DAY) from result_1005 group by DATE_SUB('2016-10-04',INTERVAL regDay DAY) ORDER BY COUNT desc 阅读全文
posted @ 2016-10-06 00:08 crac 阅读(92) 评论(0) 推荐(0) 编辑