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数据库Mark.2 

select count(*) as count,DATE_SUB('2016-10-04',INTERVAL regDay DAY)
from result_1005
group by 
DATE_SUB('2016-10-04',INTERVAL regDay DAY) 
ORDER BY COUNT desc

　　

posted on 2016-10-06 00:08  crac  阅读(92)  评论(0)  编辑  收藏  举报