(HDOJ 1019)Least Common Multiple

Least Common Multiple
Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
 

Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
 

Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
 

Sample Input
3 5 7 15 
6 4 10296 936 1287 792 1
 

Sample Output
105 
10296
 

Source
 

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JGShining
 

 AC code:

#include "stdio.h"
__int64 s[
1000];
__int64 hcf(__int64 a,__int64 b)
{
    __int64 r
=0;

    
while(b!=0)
    {
       r
=a%b;
       a
=b;
       b
=r;
    }
    
return(a);

__int64 lcd(__int64 u,__int64 v,__int64 h)
{
    
return(u*v/h);
}

int main(int argc, char* argv[])
{
 
int n,m,i;
 
while(scanf("%d",&n)==1)
 {
  
while(n--)
  {
   scanf(
"%d",&m);
   
for(i=0;i<=m-1;i++)
    scanf(
"%I64d",&s[i]);
   
for(i=0;i<=m-2;i++)
   { 
    s[i
+1]=lcd(s[i],s[i+1],hcf(s[i],s[i+1]));
   }
   printf(
"%I64d\n",s[m-1]);

  }
 }
 
return 0;

} 

posted @ 2011-04-13 21:17  cpoint  阅读(411)  评论(0编辑  收藏  举报
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