实验6

任务4

源代码

#include<stdio.h>
#define N 10
typedef struct{
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;

void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);

int main(){
    Book x[N]={ {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49,30 },
                {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    printf("图书销量排名（按销售册数）：\n");
    printf("ISBN号                 书名                      作者                 售价      销售册数\n");
    sort(x,N);  
    output(x,N);
    printf("\n图书销售总额：%.2f\n",sales_amount(x,N));
    return 0;
    
} 

void sort(Book x[],int n){
    int i,j;
    Book t;
    for(i=0;i<n-1;i++)
        for(j=0;j<n-1-i;j++){
            if(x[j].sales_count<x[j+1].sales_count){
                t=x[j];
                x[j]=x[j+1];
                x[j+1]=t;
            }
        }
}
void output(Book x[],int n){
    int i;
    for(i=0;i<n;i++){
        printf("%s   %-25s   %-20s  %-9g  %d\n",x[i].isbn,x[i].name,x[i].author,
                                        x[i].sales_price,x[i].sales_count);
    }
}
double sales_amount(Book x[],int n){
    int i;
    double total=0;
    for(i=0;i<n;i++){
        total+=x[i].sales_price*x[i].sales_count;
    }
    
    return total;
    
}
    

结果

 任务5

源代码

#include<stdio.h>
typedef struct {
    int year;
    int month;
    int day;
}date;

void input(date *pd);
int day_of_year(date d);
int compare_dates(date d1,date d2);

void test1(){
    date d;
    int i;
    printf("输入日期：（以形如2024-12-16这样的形式输入）\n");
    for(i=0;i<3;i++){
        input(&d);
        printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,
                                d.day,day_of_year(d));
    }
}
void test2(){
    date alice_birth,bob_birth;
    int i;
    int ans;
    printf("输入Alice和bob出生日期：（形如2024-12-16这样的）\n");
    for(i=0;i<3;i++){
        input(&alice_birth);
        input(&bob_birth);
        ans=compare_dates(alice_birth,bob_birth);
        if(ans==0)
            printf("alice和bob一样大\n\n");
        else if(ans==-1)
            printf("alice比bob大\n\n");
        else
            printf("alice比bob小\n\n");
             
    }
}
int main(){
    printf("测试1：输入日期，打印输出这是一年中第多少天\n");
    test1();
    printf("\n测试2：两个人年龄大小关系\n");
    test2();
}
void input(date *pd){
    scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
    
}

int day_of_year(date d){
    int x;
    if(d.month==1)
        x=d.day;
    else if(d.month==2)
        x=31+d.day;
    else if(d.month==3)
        x=59+d.day;
    else if(d.month==4)
        x=90+d.day;
    else if(d.month==5)
        x=120+d.day;
    else if(d.month==6)
        x=151+d.day;
    else if(d.month==7)
        x=181+d.day;
    else if(d.month==8)
        x=212+d.day;
    else if(d.month==9)
        x=243+d.day;
    else if(d.month==10)
        x=273+d.day;
    else if(d.month==11)
        x=304+d.day;
    else 
        x=334+d.day;
    if(d.year%400==0||(d.year%4==0&&d.year%100!=0)&&d.month>=3){
        x+=1;    
    }
    return x;
} 
int compare_dates(date d1,date d2){
    if(d1.year<d2.year)
        return -1;
    else if(d1.year>d2.year)
        return 1;
    else
        if(d1.month<d2.month)
            return -1;
        else if(d1.month>d2.month)
            return 1;
        else 
            if(d1.day<d2.day)
                return -1;
            else if(d1.day>d2.day)
                return 1;
            else
                return 0;
}

结果

任务6

源代码

#include<stdio.h>
#include<string.h>
enum Role{
    admin,student,teacher
}; 
typedef struct{
    char username[20];
    char password[20];
    enum Role type;
}Account;

void output(Account x[],int n);

int main(){
    Account x[]={{"A1001", "123456", student},
                 {"A1002", "123abcdef", student},
                  {"A1009", "xyz12121", student}, 
                 {"X1009", "9213071x", admin},
                  {"C11553", "129dfg32k", teacher},
                  {"X3005", "921kfmg917", student}};
    int n;
    n=sizeof(x)/sizeof(Account);
    
    output(x,n);
    
    return 0;
}

void output(Account x[],int n){
    int i,j;
    for(i=0;i<n;i++){
        printf("%-15s",x[i].username);
        for(j=0;j<strlen(x[i].password)+10;j++){
            if(j>strlen(x[i].password)&&j<16)
                printf(" ");
            else if(j<=strlen(x[i].password))
                printf("*");
        }
        switch(x[i].type){
            case admin:
                printf("%5s\n","admin");
                break;
            case student:
                printf("%5s\n","student");
                break;
            case teacher:
                printf("%5s\n","teacher");
                break;            
        }
    }
}

结果

 

 实验7

源代码

#include<stdio.h>
#include<string.h>

typedef struct{
    char name[20];
    char phone[12];
    int  vip;
}contact;

void set_vip_contact(contact x[],int n,char name[]);
void output(contact x[],int n);
void display(contact x[],int n);
int cmp_name(const void *a,const void *b);

#define N 10
int main(){
    contact list[N]=  {{"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0}};
    int vip_cnt,i;
    char name[20];
    
    printf("显示原始通讯录信息：\n");
    output(list,N);
    
    printf("\n输入要设置的紧急联系人个数：");
    scanf("%d",&vip_cnt);
    printf("输入%d个紧急联系人姓名：\n",vip_cnt);
    for(i=0;i<vip_cnt;i++){
        scanf("%s",name);
        set_vip_contact(list,N,name);
    } 
     
    printf("\n显示通讯录列表：(按姓名字典升序排列，紧急联系人最先显示)\n");
    display(list,N);
    
    return 0;                        
}

void set_vip_contact(contact x[],int n,char name[]){
    int i;
    for(i=0;i<n;i++){
        if(strcmp(x[i].name,name)==0){
            x[i].vip=1;
            break;
        }
    }
}
void display(contact x[],int n){
    int i,j;
    contact t;
    for(i=0;i<n;i++)
        for(j=0;j<n-1-i;j++){
            if(strcmp(x[j].name,x[j+1].name)>0){
                t=x[j];
                x[j]=x[j+1];
                x[j+1]=t;    
            }
        }
    for(i=0;i<n;i++){
        if(x[i].vip==1){
            printf("%-10s%-15s%-15c\n",x[i].name,x[i].phone,'*');
        }
    }
    for(i=0;i<n;i++){
        if(x[i].vip==0){
            printf("%-10s%-15s\n",x[i].name,x[i].phone);
        }
    }        
}
    

void output(contact x[],int n){
    int i;
    
    for(i=0;i<n;++i){
        printf("%-10s%-15s",x[i].name,x[i].phone);
        if(x[i].vip)
            printf("%5s","*");
        printf("\n");     
    } 
} 

结果