Python爬虫：使用正则表达式爬取网站电影信息

以爬取电影天堂喜剧片前5页信息为例，代码如下：

 1 # coding:UTF-8
 2 
 3 import requests
 4 import re
 5 
 6 def mov():
 7     headers={'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36',
 8          'Host':'www.dy2018.com'}
 9     #url=('https://www.dy2018.com/1/')
10     r = requests.get(url,headers=headers)
11     data = r.text.encode("latin1").decode("gbk").replace(u'\u3000', u'')
12     pattern = re.compile('<a.*?class=ulink.*?</a>.*?<a.*?href="(.*?)" class="ulink".*?title=.*?>(.*?)</a>.*?</td>.*?<td.*?style="padding-left.*?>.*?<font.*?>.*?日期：(.*?)</font>.*?<font\scolor=.*?◎评分:\s(.*?)\s.*?</font>.*?<td.*?colspan="2".*?style=.*?<p>◎片名:(.*?)\s.*?◎别名:(.*?)\s.*?导演:(.*?)\s.*?</p>.*?<p>\s.*?类型:(.*?)\s.*?<p>.*?主演:(.*?)</p>',re.S)
13     #pattern = re.compile('<font\scolor=":(.*?)</font>.*?<td\scolspan="2".*?<p>(.*?) </p>.*?<p>(.*?)</p>.*?<p>(.*?)</p>.*?</td>.*?</tr>',re.S)
14     items = re.findall(pattern,data)
15     for item in items:
16         yield{
17             'href':item[0],
18             '标题':item[1],
19             '日期':item[2],
20             '评分':item[3],
21             '片名':item[4],
22             '别名':item[5],
23             '导演':item[6],
24             '类型':item[7],
25             '主演':item[8]
26         }
27 
28 def save_file(d):
29         with open('t1.html','a',encoding='utf-8') as f:
30             f.write('\n第'+str(i)+'页\n')
31             for m in d:
32                 f.write(str(m)+'\n')
33 34 
35 for i in range(1,6):
36     d=mov()
37     if i==1:
38         url='https://www.dy2018.com/1/'
39         save_file(d)
40         print('第 1 页爬取完成！')
41     else:
42         url = ('https://www.dy2018.com/1/index_' + str(i) + '.html')
43         save_file(d)
44         print('第',i,'页爬取完成！')

电影信息爬取效果：

 

爬取下载地址代码如下：

 1 # coding:UTF-8
 2 
 3 import requests
 4 import re
 5 
 6 def hrefs():
 7     headers={'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36',
 8          'Host':'www.dy2018.com'}
 9     #url=('https://www.dy2018.com/1/')
10     r = requests.get(url,headers=headers)
11     pattern = re.compile('<a.*?class=ulink.*?</a>.*?<a.*?href="(.*?)" class="ulink"',re.S)
12     href = re.findall(pattern,r.text)
13     return href
14 
15 def inf(link):
16     for h in link:
17         durl= ('https://www.dy2018.com'+ h)
18         headers={'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36',
19              'Host':'www.dy2018.com'}
20         dr = requests.get(durl,headers=headers)
21         ddata = dr.text.encode("latin1").decode("gbk").replace(u'\u3000', u'')
22         pattern = re.compile('alt=.*?译.*?名(.*?)</p>.*?片.*?名(.*?)</p>.*?style="margin.*?href="(.*?)">.*?',re.S)
23         info = re.findall(pattern,ddata)
24         for item in info:
25             yield{
26                 #'译名':item[0],
27                 '片名':item[1],
28                 '下载地址':item[2]
29         }
30 
31 def save_file(link):
32         with open('t2.html','a',encoding='utf-8') as f:
33             #link=hrefs()
34             f.write('\n第'+str(i)+'页\n')
35             for ins in inf(link):
36                 f.write(str(ins)+'\n')
37 38 
39 for i in range(1,6):
40     if i==1:
41         url='https://www.dy2018.com/1/'
42         link=hrefs()
43         save_file(link)
44         print('第 1 页爬取完成！')
45     else:
46         url = ('https://www.dy2018.com/1/index_' + str(i) + '.html')
47         link=hrefs()
48         save_file(link)
49         print('第',i,'页爬取完成！')

爬取下载地址效果如下：

 

posted on 2018-11-08 11:59  Cooper_73  阅读(3013)  评论(0)  编辑  收藏  举报

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