摘要: Transfer function: \[\frac{1}{Ts+1} \]写成微分方程: \[Ty'(t)+y(t)=u(t) \]向前差分: \[y'(t) = \frac{y(t+1)-y(t)}{\Delta T} \\ y(t+1)=y(t)+\frac{\Delta T}{T}(u(t) 阅读全文
posted @ 2019-06-12 22:01 华小电 阅读(2910) 评论(0) 推荐(0) 编辑