摘要: 1 l1 = ['a',1,'c','b',2,'b','c','d','a'] 2 l2= sorted(set(l1),key=l1.index) 3 print('l2:',l2) 4 print('l1:',l1) 5 6 #输出 7 #l2: ['a', 1, 'c', 'b', 2, ' 阅读全文
posted @ 2017-04-25 23:39 丛影HHZ 阅读(4865) 评论(0) 推荐(0) 编辑