随笔 - 58 文章 - 1 评论 - 2 阅读 - 38646

JsonConvert.DeserializeObject<T>对象属性为空

解决方法:

给T类加上带参的构造函数，为成员变量赋值

一开始我的T类如下：

public class OrderQueryParam : QueryParam
   {
       public string TypeCode { get; set; }
       public string Type { get; set; }
       public string Status { get; set; }
       public string StartTime { get; set; }
       public string EndTime { get; set; }
       public string TraderId { get; set; }
       public string Token { get; set; }
   }

JsonConvert.DeserializeObject<OrderQueryParam>反序列化后结果部分属性为Null,

后面加了个带参构造函数（如下），就得到正确结果了

public class OrderQueryParam : QueryParam
    {
        public string TypeCode { get; set; }
        public string Type { get; set; }
        public string Status { get; set; }
        public string StartTime { get; set; }
        public string EndTime { get; set; }
        public string TraderId { get; set; }
        public string Token { get; set; }
 
        public OrderQueryParam(string typeCode,string type,string status,string startTime,string endTime,string traderId,string token)
        {
            this.TypeCode = typeCode;
            this.Type = type;
            this.Status = status;
            this.StartTime = startTime;
            this.EndTime = endTime;
            this.TraderId = traderId;
            this.Token = token;
             
        }
    }