(Easy) Sort Array By Parity (LeetCode)

Description:

Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A.

You may return any answer array that satisfies this condition.

 

Example 1:

Input: [3,1,2,4]
Output: [2,4,3,1]
The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

 

Note:

1. 1 <= A.length <= 5000
2. 0 <= A[i] <= 5000

Accepted

119,992

Submissions

165,087

 

Solution:

class Solution {
    public int[] sortArrayByParity(int[] A) {
        
        if (A==null||A.length==0){
            return null;
        }
        
        int[] B = new int[ A.length];
        int k = 0; 
        for(int i = 0; i<A.length; i++){
            
            if(A[i]%2==0){
                
                B[k++]=A[i];
            }
        }
        
        for(int i = 0; i<A.length; i++){
            
            if(A[i]%2!=0){
                
                B[k++]=A[i];
            }
        }
        
        return B;
        
    }
}