(Easy) Image Smoother LeetCode

Description:

Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.

Example 1:

Input:
[[1,1,1],
 [1,0,1],
 [1,1,1]]
Output:
[[0, 0, 0],
 [0, 0, 0],
 [0, 0, 0]]
Explanation:
For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0
For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0
For the point (1,1): floor(8/9) = floor(0.88888889) = 0

 

Note:

1. The value in the given matrix is in the range of [0, 255].
2. The length and width of the given matrix are in the range of [1, 150].

 

Accepted

38,013

Submissions

77,189

 

Solution:

 

class Solution {
    public int[][] imageSmoother(int[][] M) {
        
       int [][] res = new int[M.length][M[0].length]; 
        for(int i =0;i<M.length; i++){
            for(int j=0; j<M[0].length;j++){
                
                res[i][j] = Check(M,i,j);
                
            }
        }
        
        return res;
        
    }
    
    
     public int Check(int [][] board, int row, int col){
         int count = 1;
        int row_[] ={-1,-1,-1,0,1,1, 1,0 };
        int col_[] ={-1, 0, 1,1,1,0,-1,-1};
        int Sum=board[row][col];
       
        for(int i = 0; i<8;i++){
            
            if(0<=row+row_[i]&& row+row_[i]<=board.length-1&& 0<=col+col_[i]&&col+col_[i]<=board[0].length-1){
                  Sum = Sum + board[row+row_[i]][col+col_[i]]; 
                count++;
            }
           
        }
         
       
        return (int)Math.floor(Sum/count);
    }

}