The mutable default argument in Python
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | >>> def a(): ... print "a executed" ... return [] ... >>> >>> def b(x = a()): ... x.append( 5 ) ... print x ... a executed >>> b() [ 5 ] >>> b() [ 5 , 5 ] |
Actually, this is not a design flaw, and it is not because of internals, or performance. It comes simply from the fact that functions in Python are first-class objects, and not only a piece of code.
As soon as you get to think into this way, then it completely makes sense: a function is an object being evaluated on its definition; default parameters are kind of "member data" and therefore their state may change from one call to the other - exactly as in any other object.
In any case, Effbot has a very nice explanation of the reasons for this behavior in Default Parameter Values in Python. I found it very clear, and I really suggest reading it for a better knowledge of how function objects work.
Related Link: http://stackoverflow.com/questions/1132941/least-astonishment-in-python-the-mutable-default-argument
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
· 没有源码,如何修改代码逻辑?
· 全程不用写代码,我用AI程序员写了一个飞机大战
· MongoDB 8.0这个新功能碉堡了,比商业数据库还牛
· 记一次.NET内存居高不下排查解决与启示
· DeepSeek 开源周回顾「GitHub 热点速览」
· 白话解读 Dapr 1.15:你的「微服务管家」又秀新绝活了