题目（14）答案

#include <iostream>
#include <cstdio>

using namespace std;

int check(int a,int b)
{
	//0石头,2剪刀,3布
	if (a == 0 && b == 2)
		return 1;
	else if (a == 0 && b == 5)
		return 2;
	else if (a == 2 && b == 0)
		return 2;
	else if (a == 2 && b == 5)
		return 1;
	else if (a == 5 && b == 0)
		return 1;
	else if (a == 5 && b == 2)
		return 2;
	else
		return 0;
}

int main()
{
	int N, AN, BN;
	//indent guides
	//claudiaIDE
	/*N轮数，AN是A规律数，BN是B规律数
	10 3 4
	0 2 5
	0 5 0 2*/
	int a[101] = { 0 }, b[101] = { 0 };
	std::cin >> N;
	std::cin >> AN;
	std::cin >> BN;
	int indexA = 0;
	int indexB = 0;
	//A的规律
	for (int i = 0; i < AN; i++)
		cin >> a[i];
	//B的规律
	for (int i = 0; i < BN; i++)
		cin >> b[i];
	int ai = 0; int bi = 0;
	for (int i = 0; i < N; i++)
	{
		int x = check(a[ai], b[bi]);
		//cout << "i=" << i << " " << "x=" << x << endl;
		if (x == 1)
			indexA++;
		else if (x == 2)
			indexB++;
		//cout << "indexA=" << indexA << " " << "indexB=" << indexB << endl;
		//cout << "ai=" << ai << " " << "bi=" << bi << endl;
		ai++; bi++;
		if (ai == AN)
			ai = 0;
		if (bi == BN)
			bi = 0;
	}
	//char ans = indexA > indexB ? 'A' : 'B';
	char ans;
	if (indexA > indexB)
		ans = 'A';
	else
		ans = 'B';
	//cout << "A:" << indexA << " B:" << indexB << endl;
	cout << ans << endl;
	return 0;
}

没有任何难点。